[Solved]What's the output of this COBOL Program

rambabu · Active User Joined: 18 Apr 2005 Posts: 67

what is the out of the below program?
01 emp
05 eno pic 999.
05 ename z(4).
move 19 to eno.
move emp to ename.
display emp.
display eno.
display ename.

kvivek · Posted: Mon Jun 13, 2005 6:42 pm Post subject:

display emp - 019
display eno - 019
display ename - SPACES

Regards,
Vivek

vel2k8

Vivek,

I think you are wrong.. This should be the answer..

EMP 0190190
ENO 019
ENAME 0190

Thanks
Vel.

kvivek · Posted: Wed Jun 15, 2005 8:48 pm Post subject:

Vel,

You are correct... Sorry I haven't seen "move emp to ename" statement.

Regards,
Vivek

sudheer648

Hi rambabu,

ENO will be 019 b'coz it moves values from right.
ENAME will 0190 b'coz it moves data from left.
EMP it is group item it is printing both eno and ename.