regarding comp declarations

medepallirao · New User Joined: 05 May 2005 Posts: 6 Location: pune

please answer the questions

1. how many bytes does s9(4) comp-3 field take?
2. how many bytes does 9(4) comp-3 field take?
3. give me clear idea on PARM parameter

if i want to take 10 bytes of data by using parm parameter how can u declare it cobol and what u code in jcl

swaran_msc · New User Joined: 19 May 2005 Posts: 5 Location: Bangalore

s9(4) Comp-3 will take (n+1)/2 = 2.5 = 3 bytes.

9(4) Comp-3 will take n/2 = 2 bytes.

For Parm Parameter Refer Chapter 1 in Mvs Jcl Primer by Saba Zamir.

Corrections are Welcome...

ajay_dheepak · New User Joined: 12 May 2005 Posts: 33 Location: Chennai

For both it is 3 bytes

ajay_dheepak · New User Joined: 12 May 2005 Posts: 33 Location: Chennai

Declaration Value Internal representation
PIC S9(4) COMP-3 + 1234 01 23 4C

PIC 9(4) COMP-3 1234 01 23 4F

so for both it is 3 bytes

subhasis_50 · Moderator Joined: 09 Mar 2005 Posts: 367 Location: Earth

Hi,
Ajay is correct. It will take 3 bytes. In case of COMP-3 variable the sign is stored rightmost half a byte of character as it is the representation of packed decimal. It is not a fact that S is mentioned or not.