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on code=8091 u4039, getting s0c4 abend

 
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prasanth_thavva

Active User


Joined: 28 Jul 2005
Posts: 103
Location: Bangalore

PostPosted: Tue Dec 27, 2005 10:11 am    Post subject: on code=8091 u4039, getting s0c4 abend
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hi,

i got soc4 , the error routine showing me the following message ,

1) Display Filter View Print Options Help
-------------------------------------------------------------------------------
SDSF OUTPUT DISPLAY SP416824 JOB06516 DSID 103 LINE 0 COLUMNS 02- 81
COMMAND INPUT ===> SCROLL ===> CSR
********************************* TOP OF DATA **********************************
XYX00101 (00.01) COMPILED: 07/25/01 11.43.17 STARTED: 12/26/05 23:14:08
IBM0534S ONCODE=8094 Protection exception
From entry point _Begin_1584_Blk_11 at statement 1584 at compile unit o
+00000282 at address 3B007112.
<> LEAID ENTERED (LEVEL 05/09/2005 AT 11.27)
<> LEAID PROCESSING COMPLETE. RC=0
Storage Report for Enclave XY5T240 12/26/05 11:14:19 PM
Language Environment V01 R05.00

STACK statistics:
Initial size: 204800
Increment size: 204800
Maximum used by all concurrent threads: 129936
Largest used by any thread: 129936
Number of segments allocated: 1
Number of segments freed: 0
F1=HELP F2=SPLIT F3=END F4=RETURN F5=RFIND F6=RCHANGE
F7=UP F8=DOWN F9=SWAP F10=LEFT F11=RIGHT F12=RETRIEVE
. . . . . . . . . . . . . . . . . . . . . . . . . . .

actually the main procedure is
cmn.acis.stage.#003448.src
cmn.acis.stage.#003448.lod

actually "lod" contains the main procedure ... i am refering in my jcl . the sub procedure residing in "ldn", will it gives the SOC4 .
cmn.acis.stage.#003448.*

*<--referring to LOD,LDN.

MainProcedure(LOD) ---> Sub procedure(LDN)

while submitting jcl i got soc4...

whether i need to refer both the modules in one pds, or seperatly it picks the load modules?

Please clarify me ASAP?
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References
Bitneuker

IMS Moderator


Joined: 07 Nov 2005
Posts: 1143
Location: The Netherlands at Hole 19

PostPosted: Thu Dec 29, 2005 7:06 pm    Post subject:
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Did you have both the same AMODE? If they differ (one = 24 and the other = 31) passing pointers easely leads to protection exeption. From your topic I understand the subprocedure is outside the main programm.
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